X^2+6x=325

Solution for X^2+6x=325 equation:

X^2+6X=325

We move all terms to the left:

X^2+6X-(325)=0

a = 1; b = 6; c = -325;
Δ = b2-4ac
Δ = 62-4·1·(-325)
Δ = 1336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1336}=\sqrt{4*334}=\sqrt{4}*\sqrt{334}=2\sqrt{334}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{334}}{2*1}=\frac{-6-2\sqrt{334}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{334}}{2*1}=\frac{-6+2\sqrt{334}}{2}
$